Digital SAT Math · Algebra
Graphs of linear equations
The picture is already the solution. When the test draws a line or a shaded half-plane, the fastest path is not algebra first — it is two features read off the grid: the sign of the slope and the y-intercept. Those two kills usually leave one choice standing before you ever count rise over run.
On the test
| Domain | Algebra (score report) |
| What it looks like | A coordinate grid with one line, or one shaded region with a solid or dashed boundary |
| Often asked | “Which equation represents the line?”, “What is the slope?”, “Which inequality describes the shaded region?”, “What is the y-intercept?” |
| Format | Multiple choice and student-produced response |
| Calculator | Desmos can confirm a candidate equation, but lattice points beat keystrokes for a single line — see the box below |
Recognition cues: in the xy-plane; a graph with two marked lattice points; shaded region; solid or dashed boundary; answer choices that are four versions of or four inequalities that differ only in a symbol or a sign.
Where this skill ends and its neighbours begin
Algebra-first work on one line — points to equation, standard-form slope , parallel lines — lives on linear equations in two variables. Function language , tables, input-vs-output lives on linear functions. One-variable inequalities and word limits live on linear inequalities. This page is picture-first: the stem hands you a graph (or asks you to treat intercepts as a graph), and the job is to read it. Two boundaries at once is systems of linear inequalities — not here.
Pattern recognition
Sort by what the picture gives you:
- Match the equation — kill by sign of slope, then by y-intercept, then confirm rise/run on lattice points.
- Read one number — slope only, or one intercept only; leave the other feature alone.
- Match the inequality — boundary equation first, solid/dashed next, test point last.
- Point in / out of a half-plane — substitute; strict symbols exclude the boundary.
- Intercepts from an equation — set the other variable to 0; do not rearrange the whole line unless asked.
Method
- Read intercepts off the picture. Where the line meets the vertical axis is . Where it meets the horizontal axis is the x-intercept. Only trust crossings that land on lattice points (or that the stem labels).
- Slope by rise/run on lattice points only. Pick two points the line passes through exactly. . Never estimate between grid lines.
- Match sign-of-slope first to kill choices. Rising → positive; falling → negative. Then match . What remains is usually one equation.
- For inequalities: boundary style, then a test point. Solid means inclusive ( or ); dashed means strict ( or ). Pick any labeled point in the shaded region and substitute — the side that makes the inequality true is the answer.
Slope and intercept, from a picture
| Feature | How to read it | Common trap |
|---|---|---|
| Sign of slope | Rises or falls left-to-right | Ignoring sign and matching only steepness |
| Slope value | Rise/run between two lattice points | Run/rise (reciprocal) |
| y-intercept | Height at , or extend from a lattice point | Using a marked point’s y-coordinate when |
| x-intercept | Where | Reporting it when the question asked for |
| Inclusive boundary | Solid line, filled endpoint | Treating solid as strict |
| Side of inequality | Test a shaded point | Shading “above means greater” without checking |
Worked example 1 — match the line by sign, intercept, then slope
Stem. Line in the xy-plane passes through the lattice points and . Which equation represents ?
Choices (compressed): , , , .
Step 1 — sign of slope. From to the line falls, so . Drop every positive-slope choice.
Step 2 — y-intercept. The point sits on the vertical axis, so . Drop any choice whose constant is not 4.
Step 3 — rise/run. .
Answer: .
Trap watch. is the inverted fraction (run over rise with the sign kept). steals the marked y-coordinate at and pretends it is the intercept.
Worked example 2 — intercepts off an equation, no rearranging
Stem. What are the intercepts of the graph of ?
Step 1 — y-intercept. Set : , so . Point .
Step 2 — x-intercept. Set : , so . Point .
Step 3 — optional slope check. From to , , which matches the standard-form rule .
Answers: y-intercept 4; x-intercept 5.
Trap watch. Reporting 5 as the y-intercept (or 4 as the x-intercept) is the classic swap: students remember both numbers and attach them to the wrong axis. Setting produces the x-intercept — the zero is on the axis you are not naming.
Worked example 3 — shaded region: solid/dashed, then test
Stem. A graph shows a dashed line through and , with the region below the line shaded. Which inequality is shown?
Step 1 — boundary. Rise/run: , intercept 2. Boundary: .
Step 2 — style. Dashed means the boundary is out: strict symbol, or .
Step 3 — side. Test a point clearly below the line, say : is true, so the shaded side is “less than.”
Answer: .
Trap watch. is the solid-line twin — same side, wrong inclusion. is the dashed twin on the wrong side. Both appear whenever the test writes four inequalities that differ by one bit each.
Practice
Answer before you open the explanation. Six items depend on a figure — the numbers you need are on the grid, not in the sentence. Two items are student-produced response. Every wrong choice below is a specific, named error: inverted rise/run, intercept swap, sign of slope, solid-vs-dashed, or shading without a test.
Question 1 Warm-up
Which statement about the graph of the equation y = -3x + 5 in the xy-plane is true?
Show the answer Choice B
Why it is right
In slope-intercept form y = mx + b, the coefficient of x is the slope and the constant term is the y-intercept. Here m = -3 and b = 5, so the graph falls from left to right with slope -3 and crosses the vertical axis at (0, 5). No algebra is required — the two features are already written in the equation.
Why each other choice fails
- Choice A
- Swaps the two numbers: treats the constant 5 as the slope and the coefficient -3 as the intercept. In y = mx + b the slope is always the coefficient of x.
- Choice C
- Drops the sign of the slope. A slope of +3 would rise from left to right; the coefficient -3 means the line falls.
- Choice D
- Misnames the intercept. The constant 5 is the y-intercept (where x = 0), not the x-intercept. The x-intercept of this line is the solution of 0 = -3x + 5, which is x = 5/3, not 5.
Question 2 Standard
The graph of line k in the xy-plane is shown, with two points on the line marked. Which equation represents line k?
Show the answer Choice A
Why it is right
Kill by sign of slope first: the line rises from left to right, so the slope is positive and B is already out. The marked points are the lattice pair (0, -1) and (2, 3). Rise over run is (3 - (-1)) / (2 - 0) = 4 / 2 = 2, and the point on the vertical axis is the y-intercept -1. The equation is y = 2x - 1. Check: at x = 2, 2(2) - 1 = 3, matching the second marked point.
Why each other choice fails
- Choice B
- Uses the correct intercept with a negative slope. A slope of -2 would fall from left to right, but the graphed line rises through (0, -1) toward (2, 3).
- Choice C
- Inverts rise and run, reading 2 over 4 as the slope instead of 4 over 2. Slope is always the vertical change first.
- Choice D
- Keeps the correct slope but flips the sign of the intercept. The line meets the vertical axis at -1, not +1; y = 2x + 1 would pass through (0, 1) and (2, 5), neither of which is marked.
Question 3 Standard
What is the y-intercept of the graph of 3x + 2y = 12 in the xy-plane?
Show the answer Choice C
Why it is right
The y-intercept is the point where the graph meets the vertical axis, so set x = 0 in the equation: 2y = 12, and y = 6. The intercept is the number 6 (or the point (0, 6)). You never need the slope for this question — zeroing the other variable is enough.
Why each other choice fails
- Choice A
- Reports the coefficient of y rather than the intercept. The 2 in 2y is a coefficient in the standard-form equation, not a coordinate where the graph crosses an axis.
- Choice B
- Reports the coefficient of x. Same trap as A: coefficients are not intercepts.
- Choice D
- Reports the x-intercept instead of the y-intercept. Setting y = 0 gives 3x = 12 and x = 4, which is where the line meets the horizontal axis, not the vertical one.
Question 4 Standard
The graph of line m in the xy-plane is shown, with two points on the line marked. What is the slope of line m?
Show the answer Choice D
Why it is right
Use only the marked lattice points so no coordinate is estimated. From (1, 5) to (5, 3) the rise is 3 - 5 = -2 and the run is 5 - 1 = 4, so the slope is -2 / 4 = -1/2. The line falls gently from left to right, which matches a small negative slope.
Why each other choice fails
- Choice A
- Inverts rise and run and drops the sign: run over rise as 4 / 2. Slope is vertical change over horizontal change, and the line is falling, so the sign must be negative.
- Choice B
- Inverts rise and run but keeps a positive sign: 4 / 2 with the direction ignored. The graphed line falls, so a positive slope cannot be right.
- Choice C
- Uses the rise -2 as the slope and forgets to divide by the run 4. The change in y alone is not a rate.
Question 5 Standard
In the xy-plane, the shaded region shown is the solution set of a linear inequality. The boundary is solid. Which inequality describes the shaded region?
Show the answer Choice A
Why it is right
Read the boundary first. It crosses the y-axis at 4 and falls one unit for every unit to the right, so the boundary line is y = -x + 4. The line is solid, so the boundary itself belongs to the solution set and the symbol is inclusive (≤ or ≥). The shading lies below the line; the marked point (1, 1) confirms the side: -1 + 4 = 3 and 1 ≤ 3 is true. The inequality is y ≤ -x + 4.
Why each other choice fails
- Choice B
- Reads the solid boundary as a dashed one. A solid line includes its own points; a strict inequality would require a dashed boundary.
- Choice C
- Shades the wrong side. Testing the marked point (1, 1) gives 1 ≥ 3, which is false, so points below the line do not satisfy y ≥ -x + 4.
- Choice D
- Flips the sign of the slope. The drawn boundary falls from left to right (negative slope); y = x + 4 rises and would pass through (0, 4) and (1, 5), not through (4, 0).
Question 6 Harder
The graph of line p in the xy-plane is shown, with two points on the line marked. Which equation represents line p?
Show the answer Choice C
Why it is right
Sign of slope first: the line falls, so the slope is negative and D is out. From the marked lattice points (2, 8) and (6, 2), rise over run is (2 - 8) / (6 - 2) = -6 / 4 = -3/2. Anchor at (2, 8): 8 = (-3/2)(2) + b gives 8 = -3 + b, so b = 11. The equation is y = -3/2x + 11. Check the other point: (-3/2)(6) + 11 = -9 + 11 = 2.
Why each other choice fails
- Choice A
- Inverts rise and run, reading -4 / 6 as -2/3. The line drops 3 units for every 2 it moves right, not 2 for every 3.
- Choice B
- Takes the y-coordinate of the marked point (2, 8) as the y-intercept. The intercept is the height at x = 0; extending left from (2, 8) by 2 units raises y by 3, so the intercept is 11, not 8.
- Choice D
- Uses the correct steepness with the wrong sign. A positive slope would rise from left to right, but the graphed line falls from (2, 8) to (6, 2).
Question 7 Harder
In the xy-plane, a line has x-intercept 3 and y-intercept -6. Which equation represents the line?
Show the answer Choice B
Why it is right
The intercepts are the points (3, 0) and (0, -6). Slope is rise over run: (0 - (-6)) / (3 - 0) = 6 / 3 = 2. The y-intercept is already given as -6, so the slope-intercept equation is y = 2x - 6. Check the x-intercept: 0 = 2x - 6 gives x = 3, matching the stem.
Why each other choice fails
- Choice A
- Flips the sign of the slope. From (0, -6) to (3, 0) the line rises, so the slope is positive, not -2.
- Choice C
- Keeps the correct slope but flips the sign of the y-intercept. The line meets the vertical axis at -6, not +6.
- Choice D
- Uses the x-intercept 3 as if it were the y-intercept. The constant term in y = mx + b is the y-intercept; putting 3 there produces a line through (0, -3), not (0, -6).
Question 8 Harder
In the xy-plane, the shaded region shown is the solution set of a linear inequality. The boundary is dashed. Which inequality describes the shaded region?
Show the answer Choice A
Why it is right
The boundary crosses the y-axis at -1 and rises 2 units for every 1 unit to the right (through lattice points such as (0, -1) and (1, 1)), so the boundary line is y = 2x - 1. The line is dashed, so points on the boundary are not solutions and the symbol must be strict. Shading is above the line; the marked point (0, 2) settles the direction: 2(0) - 1 = -1 and 2 > -1 is true. The inequality is y > 2x - 1.
Why each other choice fails
- Choice B
- Reads the dashed boundary as a solid one. A solid line would include boundary points (≥); a dashed line excludes them (>).
- Choice C
- Shades the wrong side. At the marked point (0, 2), the comparison 2 < -1 is false, so points above the line do not satisfy y < 2x - 1.
- Choice D
- Inverts the slope, reading a rise of 2 over a run of 1 as 1/2. The line y = (1/2)x - 1 is much flatter and would not pass through (1, 1).
Question 9 Harder Student-produced response
In the xy-plane, a line passes through the points (-2, 7) and (4, -5). What is the slope of the line?
Show the answer -2
Why it is right
Take both differences in the same order, second point minus first. The rise is -5 - 7 = -12 and the run is 4 - (-2) = 6, so the slope is -12 / 6 = -2. Reversing both differences gives the same result: (7 - (-5)) / (-2 - 4) = 12 / (-6) = -2. A negative slope matches the drop from y = 7 to y = -5 as x increases.
Answers students type instead
- 2
- Comes from mismatched subtraction order, such as (7 - (-5)) / (4 - (-2)) = 12 / 6. Reversing only one of the two differences flips the sign.
- -1/2
- Inverts the fraction to run over rise, 6 / -12. Slope is always the change in y over the change in x.
- 1/2
- Inverts rise and run and also drops the sign. Both errors together produce a positive reciprocal of the true slope.
Question 10 Hardest
The graph of line t in the xy-plane is shown, with two points on the line marked. Which equation represents line t?
Show the answer Choice D
Why it is right
Sign of slope first: the line rises, so the slope is positive. From the marked lattice points (2, -1) and (6, 5), rise over run is (5 - (-1)) / (6 - 2) = 6 / 4 = 3/2. Anchor at (2, -1): -1 = (3/2)(2) + b gives -1 = 3 + b, so b = -4. The equation is y = 3/2x - 4. Check: (3/2)(6) - 4 = 9 - 4 = 5.
Why each other choice fails
- Choice A
- Inverts rise and run, reading 4 / 6 as 2/3. The line rises 3 units for every 2 it moves right.
- Choice B
- Keeps the correct slope but flips the sign of the intercept. The line meets the vertical axis below the origin at -4, not at +4; y = 3/2x + 4 would pass through (2, 7), not (2, -1).
- Choice C
- Takes the y-coordinate of the marked point (2, -1) as the y-intercept. The intercept is the height at x = 0; moving 2 units left from (2, -1) drops y by 3, so the intercept is -4, not -1.
Question 11 Hardest Student-produced response
What is the x-intercept of the graph of 5x - 2y = 20 in the xy-plane?
Show the answer 4
Why it is right
The x-intercept is where the graph meets the horizontal axis, so set y = 0: 5x = 20 and x = 4. The intercept value is 4 (the point is (4, 0)). No need to rearrange into slope-intercept form — zeroing the other variable is the whole method.
Answers students type instead
- 5
- Reports the coefficient of x as if it were the intercept. Coefficients in standard form are not intercept coordinates.
- 10
- Divides the constant by the coefficient of y rather than of x, or computes |20 / 2|. The x-intercept comes from 5x = 20, not from the y-coefficient.
- -10
- Reports the y-intercept instead: setting x = 0 gives -2y = 20 and y = -10. The question asked for the x-intercept.
Question 12 Hardest
Which of the following points lies in the solution set of the inequality y < -2x + 3 in the xy-plane?
Show the answer Choice B
Why it is right
A point (x, y) is in the solution set when its y-coordinate is strictly less than -2x + 3. Test each ordered pair. For (1, 0): -2(1) + 3 = 1, and 0 < 1 is true, so (1, 0) is inside the open half-plane. The inequality is strict, so points on the boundary line y = -2x + 3 are excluded; interior points below the line are included.
Why each other choice fails
- Choice A
- Lies on the boundary: at x = 0 the boundary height is 3, and 3 < 3 is false. A strict inequality never includes its boundary points.
- Choice C
- Fails the test: at x = 2 the boundary height is -4 + 3 = -1, and 0 < -1 is false. The point (2, 0) sits above the boundary line.
- Choice D
- Fails the test: at x = -1 the boundary height is 2 + 3 = 5, and 6 < 5 is false. The point (-1, 6) sits above the boundary.
Common mistakes
- Swapping rise and run — computing . The reciprocal often sits in the choices with the correct sign, which is why it survives a glance at “direction.”
- Shading without a test point — assuming “above always means greater” when the inequality is written in a rearranged form, or when the figure is the only evidence.
- Strict vs inclusive from the wrong line style — solid read as dashed (or the reverse), which flips into and changes whether boundary points count.
- Reporting the x-intercept as the y-intercept — both numbers appear in the stem or on the axes; the question names one of them.
- Using a marked point’s y-coordinate as when that point is not on the vertical axis. The intercept is the height at .
- Ignoring the sign of the slope — matching steepness only, so a falling line is paired with instead of .
- Estimating non-lattice crossings — reading “about 2.3” off the grid turns an exact slope into a number that will not appear among the choices.
- Mismatched subtraction order — . Both differences must run the same direction; reverse one and you only flip the sign.
- Treating a boundary point as a solution of a strict inequality — does not satisfy .
FAQ
Do I always need two points to match an equation? You need two independent facts. Sign of slope + y-intercept often leaves one choice; rise/run on a lattice pair confirms it. If the intercept is not lattice-clear, harvest two lattice points and compute both and .
Solid vs dashed — which symbols go with which? Solid ↔ inclusive (). Dashed ↔ strict (). The side (above/below) is a separate decision settled by a test point.
Can I use Desmos instead of counting squares? Yes for confirmation. For a single labeled lattice pair, counting is usually faster than typing. Use Desmos when you want to overlay a candidate equation on the picture you already read.
What if the line is vertical or horizontal? Horizontal means , equation . Vertical means undefined slope, equation — rare on the Digital SAT but worth recognizing so you do not force a form that cannot fit.
Is a grid-in slope allowed to be negative or fractional?
Both. Enter -3/2 exactly rather than a rounded decimal.