Digital SAT Math · Geometry & Trigonometry

Right triangle trigonometry

Every trig item on this skill lives inside one right triangle. Name the reference angle, label opposite / adjacent / hypotenuse relative to that angle only, then pick the single ratio that holds the side you know and the side (or value) you want. The test’s favorite freebie is the cofunction identity sin⁡(x∘)=cos⁡(90∘−x∘)\sin(x^\circ) = \cos(90^\circ - x^\circ) — when two acute angles sum to 90°, you often copy a number instead of computing one.

On the test

DomainGeometry and Trigonometry (score report)
What it looks likeA right triangle with side lengths, an angle of elevation, or a pure statement about complementary angles
Often asked“What is sin⁡A\sin A?”, “What is the length of…?”, “If sin⁡x∘=…\sin x^\circ = \ldots and x+y=90x + y = 90, what is cos⁡y∘\cos y^\circ?”
FormatMultiple choice and student-produced response
CalculatorAllowed throughout; degree mode on every trig evaluation — see the box below
FiguresAbout half the items arrive with a labeled right triangle; the rest state the sides or the cofunction setup in text

Recognition cues: right triangle; opposite / adjacent / hypotenuse; sin⁡\sin, cos⁡\cos, tan⁡\tan; angle of elevation; 30-60-90 or 45-45-90; two angles that sum to 90∘90^\circ.

Where this skill ends and its neighbours begin

Side lengths without a trig ratio (hidden right triangles, triples, 3D slant height) live on Pythagorean theorem & applications. Similarity and corresponding sides live on triangles. Radians, the unit circle, and signs by quadrant live on trigonometry beyond basic right triangles — anything solvable with SOH-CAH-TOA on one right triangle stays here. Angle relationships that never form a trig ratio (parallel lines, exterior angles) live on lines & angles.

Pattern recognition

Sort by what the stem hands you:

  1. Ratio from sides — three sides (or two plus a right angle) are known; read sin⁡\sin, cos⁡\cos, or tan⁡\tan of a named acute angle.
  2. Side from ratio — an angle and one side are known; solve for another side with the matching ratio (often a calculator item).
  3. Complementary cofunction — two angles sum to 90∘90^\circ, or two acute angles of one right triangle; sin⁡\sin of one equals cos⁡\cos of the other.
  4. Special right triangle — angles are 30∘30^\circ-60∘60^\circ-90∘90^\circ or 45∘45^\circ-45∘45^\circ-90∘90^\circ; exact side ratios replace the calculator.

Method

  1. Mark the reference angle. Circle the acute angle the stem names (or the elevation angle). Everything else is relative to that mark.
  2. Label opposite, adjacent, hypotenuse. Hypotenuse = side across from 90∘90^\circ. Opposite = side across from the reference angle. Adjacent = the remaining leg (touches the reference angle, not the hypotenuse).
  3. Pick the ratio that contains the known and the wanted.
    • sin⁡θ=opphyp\sin\theta = \dfrac{\text{opp}}{\text{hyp}}
    • cos⁡θ=adjhyp\cos\theta = \dfrac{\text{adj}}{\text{hyp}}
    • tan⁡θ=oppadj\tan\theta = \dfrac{\text{opp}}{\text{adj}}
  4. Solve. Cross-multiply, or multiply both sides by the denominator. For cofunction items, convert rather than compute: if x+y=90x + y = 90, then sin⁡x∘=cos⁡y∘\sin x^\circ = \cos y^\circ.
  5. Special-triangle shortcut when the angles are 30/45/6030/45/60. Use the fixed side ratios below instead of a decimal approximation unless the stem asks for a rounded length from a non-special angle.
PatternSide ratios (opposite the listed angles)
45∘45^\circ-45∘45^\circ-90∘90^\circx:x:x2x : x : x\sqrt{2} (leg : leg : hypotenuse)
30∘30^\circ-60∘60^\circ-90∘90^\circx:x3:2xx : x\sqrt{3} : 2x (opp 30∘30^\circ : opp 60∘60^\circ : hyp)
Words in the stemWhat they mean
angle of elevation / depressionacute angle between a horizontal and a line of sight — draw the right triangle
to the nearest tenthcalculator item; degree mode; round only at the end
x∘+y∘=90∘x^\circ + y^\circ = 90^\circcofunction: sin⁡x=cos⁡y\sin x = \cos y, cos⁡x=sin⁡y\cos x = \sin y; not tan⁡x=tan⁡y\tan x = \tan y
30-60-90 / isosceles rightexact radical sides; calculator optional

Worked example 1 — ratio from labeled sides

Stem. Right triangle ABCABC has a right angle at CC, with AC=8AC = 8, BC=15BC = 15, and AB=17AB = 17. What is sin⁡A\sin A?

Step 1 — reference angle AA. Opposite side is BC=15BC = 15. Adjacent side is AC=8AC = 8. Hypotenuse is AB=17AB = 17.

Step 2 — pick sine.

sin⁡A=opphyp=1517\sin A = \frac{\text{opp}}{\text{hyp}} = \frac{15}{17}

Check. Cosine would be 8/178/17 and tangent 15/815/8 — both common distractors, both wrong for this stem. Answer: 15/1715/17.

Trap watch. Reporting 8/178/17 answers cos⁡A\cos A. Reporting 15/815/8 answers tan⁡A\tan A. The ratio letters SOH / CAH / TOA only help if the sides were labeled for the angle you were asked about.

Worked example 2 — complementary angles, no triangle drawn

Stem. If sin⁡(x∘)=0.28\sin(x^\circ) = 0.28 and x∘+y∘=90∘x^\circ + y^\circ = 90^\circ, what is cos⁡(y∘)\cos(y^\circ)?

Step 1 — name the relationship. xx and yy are complementary, so sin⁡(x∘)=cos⁡(y∘)\sin(x^\circ) = \cos(y^\circ).

Step 2 — copy.

cos⁡(y∘)=0.28\cos(y^\circ) = 0.28

Check. cos⁡(x∘)=1−0.282\cos(x^\circ) = \sqrt{1 - 0.28^2} is a different question (cosine of the same angle). One-minus-sine (0.720.72) is not a trig identity at all. Answer: 0.280.28.

Trap watch. Applying the same “copy” move to tangent fails: if tan⁡(x∘)=5/12\tan(x^\circ) = 5/12 and x+y=90x + y = 90, then tan⁡(y∘)=12/5\tan(y^\circ) = 12/5, the reciprocal — not 5/125/12.

Worked example 3 — special right triangle

Stem. In a 30∘30^\circ-60∘60^\circ-90∘90^\circ triangle the hypotenuse is 1818. What is the length of the side opposite the 60∘60^\circ angle?

Step 1 — write the pattern. Opposite 30∘30^\circ, 60∘60^\circ, 90∘90^\circ: x:x3:2xx : x\sqrt{3} : 2x.

Step 2 — match the hypotenuse. 2x=18⇒x=92x = 18 \Rightarrow x = 9.

Step 3 — long leg. Opposite 60∘60^\circ is x3=93x\sqrt{3} = 9\sqrt{3}.

Check. Short leg 99, long leg 939\sqrt{3}, hyp 1818. Also 93=(18/2)39\sqrt{3} = (18/2)\sqrt{3}. Answer: 939\sqrt{3}.

Trap watch. 18318\sqrt{3} multiplies the hypotenuse by 3\sqrt{3} instead of the short leg. 929\sqrt{2} borrows the 45∘45^\circ-45∘45^\circ-90∘90^\circ radical.

Practice

Answer before opening the explanation. Five items depend on a labeled right triangle. Two items are student-produced response. Every wrong choice below is a specific error with a name — wrong reference angle, hyp used as a leg, complement applied to tangent, sine/cosine/tangent swapped, or calculator mode.

12 questions — 10 multiple choice, 2 student-produced response. Every wrong choice has its own explanation.

Question 1 Warm-up

In right triangle ABC shown, the right angle is at C. What is sin A?

C A B 8 15 17 A
Right triangle ABC with right angle at C; side lengths 8, 15, and 17.
Show the answer Choice B

Why it is right

Relative to angle A, the opposite side is BC = 15 and the hypotenuse is AB = 17. Sine is opposite over hypotenuse, so sin A = 15/17. Adjacent AC = 8 is not used for sine. Check: 8-15-17 is a scaled 8-15-17 triple, and opposite-over-hypotenuse for the angle across from 15 is 15/17.

Why each other choice fails

Choice A
This is cos A: adjacent over hypotenuse, 8/17. The stem asked for sine, which uses the opposite side 15, not the adjacent side 8.
Choice C
This is tan A: opposite over adjacent, 15/8. Tangent never divides by the hypotenuse; sine does.
Choice D
This swaps opposite and adjacent without using the hypotenuse, which is cotangent of A (or tan of the other acute angle). Sine still needs the hypotenuse in the denominator.

Question 2 Standard

In a right triangle, cos θ = 5/13 and the hypotenuse is 26. What is the length of the side adjacent to θ?

Show the answer Choice A

Why it is right

Cosine is adjacent over hypotenuse, so adj/26 = 5/13. Multiply: adj = 26 × 5/13 = 2 × 5 = 10. The triangle is a 5-12-13 triple scaled by 2 (sides 10, 24, 26), so the adjacent leg matching cos θ = 5/13 is the scaled 5, which is 10.

Why each other choice fails

Choice B
Uses sine instead of cosine: opposite = 26 × 12/13 = 24. That is the other leg; cos θ needs the adjacent leg.
Choice C
Reports the numerator of the given ratio without scaling to the actual hypotenuse of 26. The ratio 5/13 is a comparison, not a length.
Choice D
Reports the denominator of the ratio, as if the hypotenuse were 13. The stem already gives hypotenuse 26, so scale by 26/13 = 2.

Question 3 Standard

If sin(x°) = 0.28 and x° + y° = 90°, what is cos(y°)?

Show the answer Choice C

Why it is right

Angles that sum to 90° are complementary, so sin(x°) equals cos(90° − x°), which is exactly cos(y°). The given sine value therefore transfers without any further arithmetic: cos(y°) = 0.28. No calculator is required and no co-function identity beyond recognizing the complement is needed. The same number is the answer because opposite-to-x is adjacent-to-y in any right triangle that contains those two acute angles.

Why each other choice fails

Choice A
Subtracts from 1: 1 − 0.28 = 0.72. Complements swap sine with cosine; they do not send a sine value to one-minus-sine.
Choice B
Treats 0.28 as one leg of a right triangle and uses √(1 − 0.28²) ≈ 0.96 as if finding the cosine of the same angle x. The question asks for cos(y), not cos(x).
Choice D
Flips the sign. Sine and cosine of acute complementary angles are positive; the complement identity does not introduce a minus.

Question 4 Standard

In the 45-45-90 triangle shown, each leg has length 6. What is the length of the hypotenuse?

C A B 6 6 x 45° 45°
A 45-45-90 triangle with equal legs of length 6.
Show the answer Choice D

Why it is right

In a 45-45-90 triangle the sides are in the ratio 1 : 1 : √2. Each leg is 6, so the hypotenuse is 6√2. Equivalently, by Pythagoras, 6² + 6² = c² gives c² = 72 and c = √72 = 6√2.

Why each other choice fails

Choice A
Reports a leg again. The hypotenuse of an isosceles right triangle is strictly longer than either leg.
Choice B
Borrows the √3 factor from the 30-60-90 pattern. A 45-45-90 triangle uses √2 on the hypotenuse, not √3.
Choice C
Adds the legs (6 + 6) or doubles a leg. Hypotenuse length is 6√2 ≈ 8.49, not 12; Pythagoras forbids summing the legs.

Question 5 Standard

From a point on the ground 40 feet from the base of a vertical tower, the angle of elevation to the top of the tower is 32°. Which of the following is closest to the height of the tower, in feet?

A C B 40 ft h 32°
A right triangle modeling a 32° angle of elevation over a 40-foot horizontal run.
Show the answer Choice A

Why it is right

The tower is the side opposite the 32° angle of elevation and the 40-foot ground distance is the adjacent leg, so the matching ratio is tangent: height = 40 tan 32°. With the calculator in degree mode, tan 32° is approximately 0.6249, and 40 times 0.6249 is approximately 24.995, which rounds to 25.0 feet. Using sine or cosine would require the hypotenuse (the line of sight), which the stem does not give.

Why each other choice fails

Choice B
Uses sine instead of tangent: 40 sin 32° ≈ 21.2. Sine needs the hypotenuse (the line of sight), which is not given.
Choice C
Uses cosine on the ground run: 40 cos 32° ≈ 33.9. Cosine would give the adjacent side when the hypotenuse is known, not the tower height from a horizontal run.
Choice D
Inverts the tangent: 40 / tan 32° ≈ 64.0, which answers how far back you must stand to see a 40-foot tower at 32°, not the height for a 40-foot run.

Question 6 Harder

In the 30-60-90 triangle shown, the hypotenuse has length 18 and the side opposite the 30° angle has length 9. What is the length of the side opposite the 60° angle?

C A B 9 18 x 30° 60°
A 30-60-90 triangle with hypotenuse 18 and short leg 9; longer leg labeled x.
Show the answer Choice B

Why it is right

In a 30-60-90 triangle the sides opposite 30°, 60°, and 90° are in the ratio 1 : √3 : 2. The side opposite 30° is the short leg x = 9, so the side opposite 60° is x√3 = 9√3. Check against the hypotenuse: 2x = 18 matches the given hypotenuse.

Why each other choice fails

Choice A
Copies the short leg. Opposite 60° is the longer leg, always short-leg times √3.
Choice C
Multiplies the hypotenuse by √3 instead of the short leg. The long leg is (hyp/2)×√3 = 9√3, not 18√3.
Choice D
Uses the 45-45-90 radical √2 on a 30-60-90 triangle. The factor for the long leg is √3.

Question 7 Harder

In right triangle ABC, the right angle is at C. If cos A = 5/13, what is sin B?

Show the answer Choice D

Why it is right

In a right triangle the two acute angles are complementary, so A + B = 90° and sin B = cos A. Therefore sin B = 5/13. Drawing the 5-12-13 triangle confirms: if cos A = adj/hyp = 5/13, then for angle B the opposite side is that same leg of 5 and the hypotenuse is still 13, so sin B = 5/13.

Why each other choice fails

Choice A
This is sin A (or cos B) from the third side of a 5-12-13 triangle: √(13² − 5²) = 12, so sin A = 12/13. Complementary angles swap sine with cosine of the *other* angle, not sine with sine.
Choice B
Forms opposite-over-adjacent using the other leg of a 5-12-13 triangle (tan of the complementary setup without finishing). Sin B needs opposite-over-hypotenuse for B, which is 5/13, not a leg-to-leg ratio.
Choice C
Inverts the given ratio. Sine and cosine of acute angles are at most 1; 13/5 > 1 is impossible for sin B.

Question 8 Harder Student-produced response

In a right triangle, one acute angle measures 42° and the hypotenuse is 30. What is the length of the side opposite the 42° angle, rounded to the nearest tenth?

Show the answer 20.1

Why it is right

Sine is opposite over hypotenuse, so opp/30 = sin 42°. With the calculator in degree mode, sin 42° ≈ 0.6694, and opp = 30 × 0.6694 ≈ 20.073, which rounds to 20.1. Confirm the mode: if the calculator were in radians, sin(42) would be nonsense for this stem.

Answers students type instead

22.3
Uses cosine instead of sine: 30 cos 42° ≈ 22.3. Cosine returns the adjacent leg, not the opposite.
27.0
Uses tangent with the hypotenuse as if it were a leg: 30 tan 42° ≈ 27.0. Tangent needs opposite and adjacent; the 30 is the hypotenuse.
44.8
Inverts sine: 30 / sin 42° ≈ 44.8, which would be a hypotenuse given an opposite side of 30, not the reverse.

Question 9 Harder

In right triangle ABC shown, the right angle is at C. What is cos B?

C A B 9 12 15 A B
Right triangle ABC with right angle at C; side lengths 9, 12, and 15.
Show the answer Choice C

Why it is right

Relative to angle B, the adjacent leg is BC = 12 and the hypotenuse is AB = 15, so cos B = 12/15 = 4/5. (Equivalently, reduce by 3: 4/5.) Opposite to B is AC = 9, which is not used for cosine. Label sides fresh for B — do not reuse the opposite/adjacent labels you would write for angle A.

Why each other choice fails

Choice A
This is cos A (or sin B): for angle A, adjacent is 9 and hypotenuse is 15, so 9/15 = 3/5. The question asked about angle B, not A — opposite and adjacent swap when the reference angle changes.
Choice B
This is tan of an acute angle using the legs 9 and 12 (9/12 = 3/4). Cosine still needs the hypotenuse in the denominator.
Choice D
Inverts the correct cosine, giving 15/12 = 5/4. Cosine of an acute angle cannot exceed 1.

Question 10 Hardest

In a right triangle, sin(x°) = 5/13 and x° + y° = 90°. What is tan(y°)?

Show the answer Choice A

Why it is right

Build the triangle from sin x = opp/hyp = 5/13: opposite to x is 5, hypotenuse 13, so the other leg is 12. Because x and y are complementary, the side opposite y is 12 and the side adjacent to y is 5. Therefore tan y = opp/adj = 12/5. Shortcut check: tan y = tan(90° − x) = cot x = 1/tan x = 12/5.

Why each other choice fails

Choice B
This is tan x = 5/12. The complement rule for sine and cosine does not leave tangent unchanged — tan(90° − x) = cot x, the reciprocal.
Choice C
Copies sin x. Applying the sine-cosine complement identity to tangent is the named trap on this skill: sin x = cos y, but tan y is not equal to sin x.
Choice D
This is cos x (or sin y). It is a hypotenuse ratio; tangent compares the two legs only.

Question 11 Hardest Student-produced response

In a 30-60-90 triangle, the side opposite the 60° angle has length 12√3. What is the length of the side opposite the 30° angle?

Show the answer 12

Why it is right

In a 30-60-90 triangle the sides opposite 30°, 60°, and 90° are x : x√3 : 2x. The side opposite 60° is x√3 = 12√3, so x = 12. That short leg is the side opposite 30°. Check: hypotenuse would be 2x = 24, and long-leg / √3 = 12√3 / √3 = 12.

Answers students type instead

24
Reports the hypotenuse 2x = 24 rather than the short leg x = 12. Read which angle the question names.
36
Multiplies 12 by √3 again (or squares something). The move is division by √3, not another multiplication.
12√3
Copies the given long leg instead of dividing out √3. Opposite 30° is shorter than opposite 60°.
6√3
Halves the given long leg without removing √3, or confuses the pattern with half-hyp on the wrong side.

Question 12 Hardest

In a right triangle, tan A = 5/12. What is sin A?

Show the answer Choice B

Why it is right

Tangent is opposite over adjacent, so draw a right triangle with opposite 5 and adjacent 12. The hypotenuse is √(5² + 12²) = √(25 + 144) = √169 = 13. Sine is opposite over hypotenuse: sin A = 5/13. Recognizing the 5-12-13 triple makes the last step automatic.

Why each other choice fails

Choice A
Copies tan A. Sine and tangent share a numerator only when opposite is fixed, but sine divides by the hypotenuse, not by the adjacent leg.
Choice C
This is cos A = adjacent/hypotenuse = 12/13. Swapping sine and cosine is the same family of opposite/adjacent mislabels relative to A.
Choice D
Inverts tan A. That is cot A (or tan of the other acute angle), not a sine.

Common mistakes

  1. Opposite/adjacent labeled for the wrong angle — sides marked once for AA, then reused for BB. Relabel every time the reference angle changes.
  2. Hypotenuse used as a leg — tan⁡θ=opp/hyp\tan\theta = \text{opp}/\text{hyp} or a side solved as though the given length were adjacent when it is the hypotenuse.
  3. Complement identity applied to tangent — assuming tan⁡(x∘)=tan⁡(90∘−x∘)\tan(x^\circ) = \tan(90^\circ - x^\circ). The truth is tan⁡(90∘−x∘)=cot⁡(x∘)=1/tan⁡(x∘)\tan(90^\circ - x^\circ) = \cot(x^\circ) = 1/\tan(x^\circ).
  4. Calculator in radians — sin⁡42\sin 42 evaluated as sin⁡(42 rad)\sin(42\text{ rad}) instead of 42∘42^\circ. Force degree mode (or a degree symbol in Desmos) before every evaluation.
  5. Sine/cosine/tangent swapped — correct sides, wrong letter of SOH-CAH-TOA (e.g. reporting adjacent/hyp when the stem asked for sine).
  6. Special-triangle radicals mixed — 2\sqrt{2} used on a 3030-6060-9090 long leg, or 3\sqrt{3} on a 4545-4545-9090 hypotenuse.
  7. Stopping at the unit ratio — reporting 5/135/13 when the hypotenuse is 2626 and the question asked for a side length of 1010.
  8. Inverting the ratio — solving opp=hyp/sin⁡θ\text{opp} = \text{hyp} / \sin\theta when the setup was opp=hyp⋅sin⁡θ\text{opp} = \text{hyp}\cdot\sin\theta.
  9. Rounding too early — truncating tan⁡32∘\tan 32^\circ before multiplying; round only the final length when the stem says “nearest tenth.”

FAQ

Do I need to memorize exact values of sin⁡30∘\sin 30^\circ, cos⁡45∘\cos 45^\circ, …? Yes for the special angles that appear as side-ratio items: sin⁡30∘=1/2\sin 30^\circ = 1/2, cos⁡30∘=3/2\cos 30^\circ = \sqrt{3}/2, sin⁡60∘=3/2\sin 60^\circ = \sqrt{3}/2, cos⁡60∘=1/2\cos 60^\circ = 1/2, sin⁡45∘=cos⁡45∘=2/2\sin 45^\circ = \cos 45^\circ = \sqrt{2}/2. The side patterns 1:1:21:1:\sqrt{2} and 1:3:21:\sqrt{3}:2 give the same values and are often faster.

When do I use Pythagoras instead of trig? When you already know two sides and need the third, and no angle (other than the right angle) is in play — that is the Pythagorean-theorem skill. On this page Pythagoras appears only as a bridge (e.g. turn tan⁡A=5/12\tan A = 5/12 into a 55-1212-1313 triangle so you can read sin⁡A\sin A).

Does sin⁡(x∘)=cos⁡(90∘−x∘)\sin(x^\circ) = \cos(90^\circ - x^\circ) work in radians too? Yes as an identity: sin⁡x=cos⁡(π/2−x)\sin x = \cos(\pi/2 - x). On the Digital SAT, radian forms of that identity belong with unit-circle work on trigonometry-extended. Every item on this page states angles in degrees.

How do I enter a radical on a grid-in? Most SPR items on this skill ask for a decimal (nearest tenth) or a plain integer short leg. If a stem ever demands an exact radical, the Bluebook accepts equivalent forms — but our practice SPRs here are integers or one-decimal answers.

Angle of depression vs elevation? Both are measured from the horizontal. Elevation looks up; depression looks down. The right triangle you draw is the same shape — the horizontal run is adjacent and the vertical rise/drop is opposite when the angle sits at the observer.