Digital SAT Math · Geometry & Trigonometry
Right triangle trigonometry
Every trig item on this skill lives inside one right triangle. Name the reference angle, label opposite / adjacent / hypotenuse relative to that angle only, then pick the single ratio that holds the side you know and the side (or value) you want. The test’s favorite freebie is the cofunction identity — when two acute angles sum to 90°, you often copy a number instead of computing one.
On the test
| Domain | Geometry and Trigonometry (score report) |
| What it looks like | A right triangle with side lengths, an angle of elevation, or a pure statement about complementary angles |
| Often asked | “What is ?”, “What is the length of…?”, “If and , what is ?” |
| Format | Multiple choice and student-produced response |
| Calculator | Allowed throughout; degree mode on every trig evaluation — see the box below |
| Figures | About half the items arrive with a labeled right triangle; the rest state the sides or the cofunction setup in text |
Recognition cues: right triangle; opposite / adjacent / hypotenuse; , , ; angle of elevation; 30-60-90 or 45-45-90; two angles that sum to .
Where this skill ends and its neighbours begin
Side lengths without a trig ratio (hidden right triangles, triples, 3D slant height) live on Pythagorean theorem & applications. Similarity and corresponding sides live on triangles. Radians, the unit circle, and signs by quadrant live on trigonometry beyond basic right triangles — anything solvable with SOH-CAH-TOA on one right triangle stays here. Angle relationships that never form a trig ratio (parallel lines, exterior angles) live on lines & angles.
Pattern recognition
Sort by what the stem hands you:
- Ratio from sides — three sides (or two plus a right angle) are known; read , , or of a named acute angle.
- Side from ratio — an angle and one side are known; solve for another side with the matching ratio (often a calculator item).
- Complementary cofunction — two angles sum to , or two acute angles of one right triangle; of one equals of the other.
- Special right triangle — angles are -- or --; exact side ratios replace the calculator.
Method
- Mark the reference angle. Circle the acute angle the stem names (or the elevation angle). Everything else is relative to that mark.
- Label opposite, adjacent, hypotenuse. Hypotenuse = side across from . Opposite = side across from the reference angle. Adjacent = the remaining leg (touches the reference angle, not the hypotenuse).
- Pick the ratio that contains the known and the wanted.
- Solve. Cross-multiply, or multiply both sides by the denominator. For cofunction items, convert rather than compute: if , then .
- Special-triangle shortcut when the angles are . Use the fixed side ratios below instead of a decimal approximation unless the stem asks for a rounded length from a non-special angle.
| Pattern | Side ratios (opposite the listed angles) |
|---|---|
| -- | (leg : leg : hypotenuse) |
| -- | (opp : opp : hyp) |
| Words in the stem | What they mean |
|---|---|
| angle of elevation / depression | acute angle between a horizontal and a line of sight — draw the right triangle |
| to the nearest tenth | calculator item; degree mode; round only at the end |
| cofunction: , ; not | |
| 30-60-90 / isosceles right | exact radical sides; calculator optional |
Worked example 1 — ratio from labeled sides
Stem. Right triangle has a right angle at , with , , and . What is ?
Step 1 — reference angle . Opposite side is . Adjacent side is . Hypotenuse is .
Step 2 — pick sine.
Check. Cosine would be and tangent — both common distractors, both wrong for this stem. Answer: .
Trap watch. Reporting answers . Reporting answers . The ratio letters SOH / CAH / TOA only help if the sides were labeled for the angle you were asked about.
Worked example 2 — complementary angles, no triangle drawn
Stem. If and , what is ?
Step 1 — name the relationship. and are complementary, so .
Step 2 — copy.
Check. is a different question (cosine of the same angle). One-minus-sine () is not a trig identity at all. Answer: .
Trap watch. Applying the same “copy” move to tangent fails: if and , then , the reciprocal — not .
Worked example 3 — special right triangle
Stem. In a -- triangle the hypotenuse is . What is the length of the side opposite the angle?
Step 1 — write the pattern. Opposite , , : .
Step 2 — match the hypotenuse. .
Step 3 — long leg. Opposite is .
Check. Short leg , long leg , hyp . Also . Answer: .
Trap watch. multiplies the hypotenuse by instead of the short leg. borrows the -- radical.
Practice
Answer before opening the explanation. Five items depend on a labeled right triangle. Two items are student-produced response. Every wrong choice below is a specific error with a name — wrong reference angle, hyp used as a leg, complement applied to tangent, sine/cosine/tangent swapped, or calculator mode.
Question 1 Warm-up
In right triangle ABC shown, the right angle is at C. What is sin A?
Show the answer Choice B
Why it is right
Relative to angle A, the opposite side is BC = 15 and the hypotenuse is AB = 17. Sine is opposite over hypotenuse, so sin A = 15/17. Adjacent AC = 8 is not used for sine. Check: 8-15-17 is a scaled 8-15-17 triple, and opposite-over-hypotenuse for the angle across from 15 is 15/17.
Why each other choice fails
- Choice A
- This is cos A: adjacent over hypotenuse, 8/17. The stem asked for sine, which uses the opposite side 15, not the adjacent side 8.
- Choice C
- This is tan A: opposite over adjacent, 15/8. Tangent never divides by the hypotenuse; sine does.
- Choice D
- This swaps opposite and adjacent without using the hypotenuse, which is cotangent of A (or tan of the other acute angle). Sine still needs the hypotenuse in the denominator.
Question 2 Standard
In a right triangle, cos θ = 5/13 and the hypotenuse is 26. What is the length of the side adjacent to θ?
Show the answer Choice A
Why it is right
Cosine is adjacent over hypotenuse, so adj/26 = 5/13. Multiply: adj = 26 × 5/13 = 2 × 5 = 10. The triangle is a 5-12-13 triple scaled by 2 (sides 10, 24, 26), so the adjacent leg matching cos θ = 5/13 is the scaled 5, which is 10.
Why each other choice fails
- Choice B
- Uses sine instead of cosine: opposite = 26 × 12/13 = 24. That is the other leg; cos θ needs the adjacent leg.
- Choice C
- Reports the numerator of the given ratio without scaling to the actual hypotenuse of 26. The ratio 5/13 is a comparison, not a length.
- Choice D
- Reports the denominator of the ratio, as if the hypotenuse were 13. The stem already gives hypotenuse 26, so scale by 26/13 = 2.
Question 3 Standard
If sin(x°) = 0.28 and x° + y° = 90°, what is cos(y°)?
Show the answer Choice C
Why it is right
Angles that sum to 90° are complementary, so sin(x°) equals cos(90° − x°), which is exactly cos(y°). The given sine value therefore transfers without any further arithmetic: cos(y°) = 0.28. No calculator is required and no co-function identity beyond recognizing the complement is needed. The same number is the answer because opposite-to-x is adjacent-to-y in any right triangle that contains those two acute angles.
Why each other choice fails
- Choice A
- Subtracts from 1: 1 − 0.28 = 0.72. Complements swap sine with cosine; they do not send a sine value to one-minus-sine.
- Choice B
- Treats 0.28 as one leg of a right triangle and uses √(1 − 0.28²) ≈ 0.96 as if finding the cosine of the same angle x. The question asks for cos(y), not cos(x).
- Choice D
- Flips the sign. Sine and cosine of acute complementary angles are positive; the complement identity does not introduce a minus.
Question 4 Standard
In the 45-45-90 triangle shown, each leg has length 6. What is the length of the hypotenuse?
Show the answer Choice D
Why it is right
In a 45-45-90 triangle the sides are in the ratio 1 : 1 : √2. Each leg is 6, so the hypotenuse is 6√2. Equivalently, by Pythagoras, 6² + 6² = c² gives c² = 72 and c = √72 = 6√2.
Why each other choice fails
- Choice A
- Reports a leg again. The hypotenuse of an isosceles right triangle is strictly longer than either leg.
- Choice B
- Borrows the √3 factor from the 30-60-90 pattern. A 45-45-90 triangle uses √2 on the hypotenuse, not √3.
- Choice C
- Adds the legs (6 + 6) or doubles a leg. Hypotenuse length is 6√2 ≈ 8.49, not 12; Pythagoras forbids summing the legs.
Question 5 Standard
From a point on the ground 40 feet from the base of a vertical tower, the angle of elevation to the top of the tower is 32°. Which of the following is closest to the height of the tower, in feet?
Show the answer Choice A
Why it is right
The tower is the side opposite the 32° angle of elevation and the 40-foot ground distance is the adjacent leg, so the matching ratio is tangent: height = 40 tan 32°. With the calculator in degree mode, tan 32° is approximately 0.6249, and 40 times 0.6249 is approximately 24.995, which rounds to 25.0 feet. Using sine or cosine would require the hypotenuse (the line of sight), which the stem does not give.
Why each other choice fails
- Choice B
- Uses sine instead of tangent: 40 sin 32° ≈ 21.2. Sine needs the hypotenuse (the line of sight), which is not given.
- Choice C
- Uses cosine on the ground run: 40 cos 32° ≈ 33.9. Cosine would give the adjacent side when the hypotenuse is known, not the tower height from a horizontal run.
- Choice D
- Inverts the tangent: 40 / tan 32° ≈ 64.0, which answers how far back you must stand to see a 40-foot tower at 32°, not the height for a 40-foot run.
Question 6 Harder
In the 30-60-90 triangle shown, the hypotenuse has length 18 and the side opposite the 30° angle has length 9. What is the length of the side opposite the 60° angle?
Show the answer Choice B
Why it is right
In a 30-60-90 triangle the sides opposite 30°, 60°, and 90° are in the ratio 1 : √3 : 2. The side opposite 30° is the short leg x = 9, so the side opposite 60° is x√3 = 9√3. Check against the hypotenuse: 2x = 18 matches the given hypotenuse.
Why each other choice fails
- Choice A
- Copies the short leg. Opposite 60° is the longer leg, always short-leg times √3.
- Choice C
- Multiplies the hypotenuse by √3 instead of the short leg. The long leg is (hyp/2)×√3 = 9√3, not 18√3.
- Choice D
- Uses the 45-45-90 radical √2 on a 30-60-90 triangle. The factor for the long leg is √3.
Question 7 Harder
In right triangle ABC, the right angle is at C. If cos A = 5/13, what is sin B?
Show the answer Choice D
Why it is right
In a right triangle the two acute angles are complementary, so A + B = 90° and sin B = cos A. Therefore sin B = 5/13. Drawing the 5-12-13 triangle confirms: if cos A = adj/hyp = 5/13, then for angle B the opposite side is that same leg of 5 and the hypotenuse is still 13, so sin B = 5/13.
Why each other choice fails
- Choice A
- This is sin A (or cos B) from the third side of a 5-12-13 triangle: √(13² − 5²) = 12, so sin A = 12/13. Complementary angles swap sine with cosine of the *other* angle, not sine with sine.
- Choice B
- Forms opposite-over-adjacent using the other leg of a 5-12-13 triangle (tan of the complementary setup without finishing). Sin B needs opposite-over-hypotenuse for B, which is 5/13, not a leg-to-leg ratio.
- Choice C
- Inverts the given ratio. Sine and cosine of acute angles are at most 1; 13/5 > 1 is impossible for sin B.
Question 8 Harder Student-produced response
In a right triangle, one acute angle measures 42° and the hypotenuse is 30. What is the length of the side opposite the 42° angle, rounded to the nearest tenth?
Show the answer 20.1
Why it is right
Sine is opposite over hypotenuse, so opp/30 = sin 42°. With the calculator in degree mode, sin 42° ≈ 0.6694, and opp = 30 × 0.6694 ≈ 20.073, which rounds to 20.1. Confirm the mode: if the calculator were in radians, sin(42) would be nonsense for this stem.
Answers students type instead
- 22.3
- Uses cosine instead of sine: 30 cos 42° ≈ 22.3. Cosine returns the adjacent leg, not the opposite.
- 27.0
- Uses tangent with the hypotenuse as if it were a leg: 30 tan 42° ≈ 27.0. Tangent needs opposite and adjacent; the 30 is the hypotenuse.
- 44.8
- Inverts sine: 30 / sin 42° ≈ 44.8, which would be a hypotenuse given an opposite side of 30, not the reverse.
Question 9 Harder
In right triangle ABC shown, the right angle is at C. What is cos B?
Show the answer Choice C
Why it is right
Relative to angle B, the adjacent leg is BC = 12 and the hypotenuse is AB = 15, so cos B = 12/15 = 4/5. (Equivalently, reduce by 3: 4/5.) Opposite to B is AC = 9, which is not used for cosine. Label sides fresh for B — do not reuse the opposite/adjacent labels you would write for angle A.
Why each other choice fails
- Choice A
- This is cos A (or sin B): for angle A, adjacent is 9 and hypotenuse is 15, so 9/15 = 3/5. The question asked about angle B, not A — opposite and adjacent swap when the reference angle changes.
- Choice B
- This is tan of an acute angle using the legs 9 and 12 (9/12 = 3/4). Cosine still needs the hypotenuse in the denominator.
- Choice D
- Inverts the correct cosine, giving 15/12 = 5/4. Cosine of an acute angle cannot exceed 1.
Question 10 Hardest
In a right triangle, sin(x°) = 5/13 and x° + y° = 90°. What is tan(y°)?
Show the answer Choice A
Why it is right
Build the triangle from sin x = opp/hyp = 5/13: opposite to x is 5, hypotenuse 13, so the other leg is 12. Because x and y are complementary, the side opposite y is 12 and the side adjacent to y is 5. Therefore tan y = opp/adj = 12/5. Shortcut check: tan y = tan(90° − x) = cot x = 1/tan x = 12/5.
Why each other choice fails
- Choice B
- This is tan x = 5/12. The complement rule for sine and cosine does not leave tangent unchanged — tan(90° − x) = cot x, the reciprocal.
- Choice C
- Copies sin x. Applying the sine-cosine complement identity to tangent is the named trap on this skill: sin x = cos y, but tan y is not equal to sin x.
- Choice D
- This is cos x (or sin y). It is a hypotenuse ratio; tangent compares the two legs only.
Question 11 Hardest Student-produced response
In a 30-60-90 triangle, the side opposite the 60° angle has length 12√3. What is the length of the side opposite the 30° angle?
Show the answer 12
Why it is right
In a 30-60-90 triangle the sides opposite 30°, 60°, and 90° are x : x√3 : 2x. The side opposite 60° is x√3 = 12√3, so x = 12. That short leg is the side opposite 30°. Check: hypotenuse would be 2x = 24, and long-leg / √3 = 12√3 / √3 = 12.
Answers students type instead
- 24
- Reports the hypotenuse 2x = 24 rather than the short leg x = 12. Read which angle the question names.
- 36
- Multiplies 12 by √3 again (or squares something). The move is division by √3, not another multiplication.
- 12√3
- Copies the given long leg instead of dividing out √3. Opposite 30° is shorter than opposite 60°.
- 6√3
- Halves the given long leg without removing √3, or confuses the pattern with half-hyp on the wrong side.
Question 12 Hardest
In a right triangle, tan A = 5/12. What is sin A?
Show the answer Choice B
Why it is right
Tangent is opposite over adjacent, so draw a right triangle with opposite 5 and adjacent 12. The hypotenuse is √(5² + 12²) = √(25 + 144) = √169 = 13. Sine is opposite over hypotenuse: sin A = 5/13. Recognizing the 5-12-13 triple makes the last step automatic.
Why each other choice fails
- Choice A
- Copies tan A. Sine and tangent share a numerator only when opposite is fixed, but sine divides by the hypotenuse, not by the adjacent leg.
- Choice C
- This is cos A = adjacent/hypotenuse = 12/13. Swapping sine and cosine is the same family of opposite/adjacent mislabels relative to A.
- Choice D
- Inverts tan A. That is cot A (or tan of the other acute angle), not a sine.
Common mistakes
- Opposite/adjacent labeled for the wrong angle — sides marked once for , then reused for . Relabel every time the reference angle changes.
- Hypotenuse used as a leg — or a side solved as though the given length were adjacent when it is the hypotenuse.
- Complement identity applied to tangent — assuming . The truth is .
- Calculator in radians — evaluated as instead of . Force degree mode (or a degree symbol in Desmos) before every evaluation.
- Sine/cosine/tangent swapped — correct sides, wrong letter of SOH-CAH-TOA (e.g. reporting adjacent/hyp when the stem asked for sine).
- Special-triangle radicals mixed — used on a -- long leg, or on a -- hypotenuse.
- Stopping at the unit ratio — reporting when the hypotenuse is and the question asked for a side length of .
- Inverting the ratio — solving when the setup was .
- Rounding too early — truncating before multiplying; round only the final length when the stem says “nearest tenth.”
FAQ
Do I need to memorize exact values of , , …? Yes for the special angles that appear as side-ratio items: , , , , . The side patterns and give the same values and are often faster.
When do I use Pythagoras instead of trig? When you already know two sides and need the third, and no angle (other than the right angle) is in play — that is the Pythagorean-theorem skill. On this page Pythagoras appears only as a bridge (e.g. turn into a -- triangle so you can read ).
Does work in radians too? Yes as an identity: . On the Digital SAT, radian forms of that identity belong with unit-circle work on trigonometry-extended. Every item on this page states angles in degrees.
How do I enter a radical on a grid-in? Most SPR items on this skill ask for a decimal (nearest tenth) or a plain integer short leg. If a stem ever demands an exact radical, the Bluebook accepts equivalent forms — but our practice SPRs here are integers or one-decimal answers.
Angle of depression vs elevation? Both are measured from the horizontal. Elevation looks up; depression looks down. The right triangle you draw is the same shape — the horizontal run is adjacent and the vertical rise/drop is opposite when the angle sits at the observer.