Digital SAT Math · Geometry & Trigonometry
Trigonometry beyond basic right triangles
Right-triangle SOH-CAH-TOA is not enough for every trig item on the Digital SAT. A short slice of the test puts an angle in standard position on the coordinate plane, asks for , , or at a special or quadrantal measure, or asks you to convert degrees ↔ radians. The arithmetic is tiny; the charge is for where the angle sits and which sign that quadrant forces.
On the test
| Domain | Geometry and Trigonometry (score report) |
| What it looks like | An angle in degrees or radians (often with ); a unit circle or ray from the origin; a request for , , , a coordinate, or a converted measure |
| Often asked | “What is ?”, “Convert to radians”, “The terminal point is ; what is ?” |
| Format | Multiple choice and student-produced response |
| Calculator | Allowed; mode matters — Desmos/your calculator in degree mode will mangle a -radian input |
Recognition cues: in an angle measure; the words unit circle, standard position, terminal side, radians; a diagram with a circle of radius 1 centered at the origin; choices that differ only by a sign.
What this page owns
This page owns conversion, unit-circle values at quadrantal and special angles, and sign by quadrant. Anything that is only SOH-CAH-TOA on a drawn right triangle belongs on right-triangle trigonometry. Arc length, sector area, and the circle equation belong on circles (and coordinate geometry for the equation form). Here the circle is only a unit circle used to read .
Pattern recognition
Five shapes cover essentially every item:
- Convert — degrees → radians or radians → degrees with .
- Quadrantal — , , , (and coterminal copies); answers are , , or .
- Special angle, Q1 value — reference (or ) with the usual half-radical values.
- Sign by quadrant — same magnitude as the reference angle; sign from ASTC (or from the unit-circle coordinates).
- Coterminal reduce first — angle outside reduced by before reading the value.
Method
- Convert with one identity only. radians . Degrees → radians: multiply by . Radians → degrees: multiply by . Cancel when it sits in both numerator and denominator; reduce the fraction.
- Place the angle. Sketch a ray from the origin, counterclockwise from the positive -axis (negative angles go clockwise). Name the quadrant or the axis.
- Reference angle from the -axis. In QI the reference is the angle itself. QII: (or ). QIII: (or ). QIV: (or ). The reference is always between and .
- Recall the Q1 value, then sign. Memorize (or rebuild from -- and --):
| Reference | |||
|---|---|---|---|
| () | |||
| () | |||
| () | |||
| () | undefined |
- Sign from the quadrant (ASTC). All positive in I; Sine (and csc) positive in II; Tangent (and cot) positive in III; Cosine (and sec) positive in IV. On the unit circle: , , so the sign of cosine is the sign of and the sign of sine is the sign of .
| Quadrant | |||
|---|---|---|---|
| I | |||
| II | |||
| III | |||
| IV |
Worked example 1 — convert, then stop
Stem. Convert to radians.
Step 1 — apply the factor. Degrees to radians multiplies by :
Step 2 — reduce. and share a factor of : .
Check. is a bit less than , so a bit less than — matches . Inverted factor is huge and not a special angle. Answer: .
Trap watch. Multiplying by instead of is the inverted conversion. Writing drops the . Writing doubles the angle into QIV.
Worked example 2 — quadrant, reference, sign
Stem. What is the value of ?
Step 1 — place. , so quadrant II.
Step 2 — reference from the -axis.
Step 3 — Q1 value. .
Step 4 — sign in QII. Cosine is negative in QII (ASTC: only sine is positive).
Check. On the unit circle the terminal point in QII near the negative -axis has negative and about , . Answer: .
Trap watch. Dropping the sign gives . Measuring the reference from the -axis as swaps to . Reporting answers the wrong function.
Worked example 3 — unit-circle coordinate
Stem. An angle in standard position has terminal point on the unit circle in quadrant III, and the reference angle is . What is the -coordinate of ?
Step 1 — means sine. On the unit circle, .
Step 2 — Q1 value for reference . .
Step 3 — sign in QIII. Sine is negative in QIII.
Check. QIII means both and negative, so cosine would be for the same reference. The stem asked for , not . Answer: .
Trap watch. Reporting drops the QIII sign. Reporting uses the cosine value (or confuses with ). Reporting the reference angle itself as a coordinate is not a coordinate.
Practice
Answer before opening the explanation. Three items hand you a unit circle figure — the value you need is the coordinate or the angle the diagram forces, not a number sitting in the sentence. Two are student-produced response. Every wrong choice below is one named slip: inverted conversion, wrong-axis reference, sign drop, or the wrong special value.
Question 1 Warm-up
Which of the following is the radian measure of a 90° angle?
Show the answer Choice A
Why it is right
Degrees convert to radians by multiplying by π/180. So 90 · (π/180) = 90π/180 = π/2. A right angle is one-quarter of a full turn; a full turn is 2π radians, so one quarter is (2π)/4 = π/2, which matches.
Why each other choice fails
- Choice B
- Halves 90° incorrectly into a 45° angle, whose radian measure is π/4. The conversion is 90 · π/180 = π/2, not π/4.
- Choice C
- Uses a full rotation (360° = 2π radians) instead of a quarter rotation. 90° is one-fourth of 360°, so the radian measure is one-fourth of 2π.
- Choice D
- Multiplies 90 by π and forgets to divide by 180. The conversion factor is π/180, not π alone.
Question 2 Standard
What is the degree measure of an angle of 3π/4 radians?
Show the answer Choice B
Why it is right
Radians convert to degrees by multiplying by 180/π. So (3π/4) · (180/π) = 3 · 180 / 4 = 540/4 = 135. The π cancels, leaving a pure degree measure. 135° sits in quadrant II, consistent with 3π/4 being three-quarters of the way from 0 to π.
Why each other choice fails
- Choice A
- Uses 100 in place of 180 in the conversion, computing (3/4)·100 = 75. The identity is π rad = 180°, not 100°.
- Choice C
- Converts 4π/3 instead of 3π/4: (4π/3)·(180/π) = 240. The numerator and denominator of the coefficient were swapped.
- Choice D
- Treats the angle as three-quarters of a full turn: (3/4)·360 = 270. A full turn in radians is 2π, not π, so three-quarters of a turn is 3π/2, not 3π/4.
Question 3 Standard
The figure shows an angle of 3π/2 radians in standard position on the unit circle. What is the value of cos(3π/2)?
Show the answer Choice C
Why it is right
The terminal side of 3π/2 lies on the negative y-axis, so the unit-circle point is (0, −1). Cosine is the x-coordinate of that point, which is 0. Equivalently, 3π/2 is a quadrantal angle with cos = 0 and sin = −1.
Why each other choice fails
- Choice A
- Reports the cosine of π (or the sine of 3π/2 with the wrong function). At 3π/2 the point is (0, −1), so cosine is 0 and sine is −1.
- Choice B
- Reports the cosine of 0 (the positive x-axis). The figure's ray points down the negative y-axis, not along the positive x-axis.
- Choice D
- Invents a special-angle half value for a quadrantal angle. Quadrantal cosines are only −1, 0, or 1 — never 1/2.
Question 4 Standard
What is the value of sin(2π/3)?
Show the answer Choice D
Why it is right
2π/3 is between π/2 and π, so it lies in quadrant II. The reference angle from the positive x-axis is π − 2π/3 = π/3. Then sin(π/3) = √3/2, and sine is positive in quadrant II, so sin(2π/3) = √3/2.
Why each other choice fails
- Choice A
- Uses the correct magnitude √3/2 but attaches a negative sign. Sine is positive in quadrant II; the negative would be correct for sine in QIII or QIV.
- Choice B
- Reports cos(2π/3) with the sign flipped, or uses the 30° reference value instead of 60°. The reference for 2π/3 is π/3, whose sine is √3/2, not 1/2.
- Choice C
- Combines the cosine magnitude of the reference angle with a negative sign — cos(π/3) = 1/2 and cos is negative in QII, which is cos(2π/3), not sin(2π/3).
Question 5 Standard Student-produced response
An angle measures 7π/6 radians. What is the degree measure of this angle?
Show the answer 210
Why it is right
Multiply by 180/π to convert radians to degrees: (7π/6) · (180/π) = 7 · 180 / 6 = 1260 / 6 = 210. So 7π/6 radians equals 210°. That is 30° past 180°, which matches a reference angle of π/6 in quadrant III.
Answers students type instead
- 30
- Reports only the reference angle in degrees (π/6 → 30°) and forgets to rebuild the original angle in its quadrant.
- 150
- Converts 5π/6 instead of 7π/6, or subtracts 30° from 180° and stops as if the angle were in QII. 7π/6 is past π, so the degree measure is 180 + 30 = 210, not 150.
- 420
- Multiplies 7/6 by 360 instead of 180, treating the coefficient as a fraction of a full turn rather than a fraction of π.
Question 6 Harder
The figure shows an angle of 2π/3 radians in standard position on the unit circle. What is the x-coordinate of the point where the terminal side meets the unit circle?
Show the answer Choice A
Why it is right
On the unit circle the x-coordinate is cos(θ). For θ = 2π/3 (quadrant II), the reference angle is π − 2π/3 = π/3, and cos(π/3) = 1/2. Cosine is negative in quadrant II, so cos(2π/3) = −1/2. That is the x-coordinate of the terminal point.
Why each other choice fails
- Choice B
- Drops the quadrant II sign. The magnitude 1/2 is correct for the reference angle π/3, but cosine must be negative when the terminal side is in QII.
- Choice C
- Reports sin(2π/3) with a wrong (negative) sign, or measures the reference from the y-axis and then signs as cosine. The y-coordinate is +√3/2; the x-coordinate is −1/2.
- Choice D
- Reports the positive sine of the angle — the y-coordinate rather than the x-coordinate. On the unit circle, x = cos θ and y = sin θ.
Question 7 Harder
What is the value of cos(5π/4)?
Show the answer Choice B
Why it is right
5π/4 lies between π and 3π/2, so it is in quadrant III. The reference angle measured to the nearest x-axis is 5π/4 − π = π/4. The first-quadrant value is cos(π/4) = √2/2. Cosine is negative in quadrant III (ASTC: only tangent is positive there), so cos(5π/4) = −√2/2. On the unit circle both coordinates of the terminal point are negative at this angle.
Why each other choice fails
- Choice A
- Keeps the Q1 magnitude and drops the sign. In quadrant III both sine and cosine are negative, so the cosine cannot be positive.
- Choice C
- Uses a 30°/60° special value (√3/2) instead of the 45° value required by reference π/4. The reference for 5π/4 is π/4, not π/6.
- Choice D
- Combines the wrong special magnitude with a positive sign — two errors that do not cancel into the key.
Question 8 Harder
What is the value of tan(5π/3)?
Show the answer Choice C
Why it is right
5π/3 is in quadrant IV (between 3π/2 and 2π). The reference angle is 2π − 5π/3 = π/3. Then tan(π/3) = √3, and tangent is negative in quadrant IV, so tan(5π/3) = −√3. As a check: sin(5π/3) = −√3/2 and cos(5π/3) = 1/2, so the quotient is (−√3/2)/(1/2) = −√3.
Why each other choice fails
- Choice A
- Drops the quadrant IV sign. Tangent is positive in QI and QIII only; in QIV it is negative.
- Choice B
- Uses tan(π/6) = 1/√3 instead of tan(π/3) = √3 — the 30° value for a 60° reference — and also drops the needed negative sign.
- Choice D
- Uses the 30° tangent magnitude with the correct QIV sign. The reference for 5π/3 is π/3, whose tangent is √3, not 1/√3.
Question 9 Harder Student-produced response
What is the value of sin(7π/6)?
Show the answer -1/2
Why it is right
7π/6 is between π and 3π/2, so it is in quadrant III. The reference angle is 7π/6 − π = π/6. Then sin(π/6) = 1/2, and sine is negative in quadrant III, so sin(7π/6) = −1/2. On the unit circle the terminal point is (−√3/2, −1/2); the y-coordinate is the sine.
Answers students type instead
- 1/2
- Drops the quadrant III sign and reports the positive Q1 sine of the reference angle π/6.
- √3/2
- Uses sin(π/3) instead of sin(π/6) — wrong-axis or 30°/60° swap — and usually without the required negative sign.
- -√3/2
- Reports cos(7π/6) instead of sin(7π/6). Cosine is the x-coordinate −√3/2; sine is the y-coordinate −1/2.
Question 10 Hardest
The figure shows an angle of 11π/6 radians in standard position on the unit circle. What is the y-coordinate of the point where the terminal side meets the unit circle?
Show the answer Choice D
Why it is right
On the unit circle the y-coordinate is sin(θ). For θ = 11π/6 (quadrant IV), the reference angle is 2π − 11π/6 = π/6. Then sin(π/6) = 1/2, and sine is negative in quadrant IV, so sin(11π/6) = −1/2. That is the y-coordinate of the terminal point.
Why each other choice fails
- Choice A
- Drops the quadrant IV sign. The magnitude matches the reference π/6, but the terminal side is below the x-axis, so y must be negative.
- Choice B
- Uses the cosine magnitude of the reference (or sin of π/3) with a positive sign — both the wrong function/value and the wrong sign for y in QIV.
- Choice C
- Reports cos(11π/6) with a wrong sign, or swaps sine and cosine after taking reference π/3. The x-coordinate is +√3/2; the y-coordinate is −1/2.
Question 11 Hardest
Angle θ satisfies cos θ = −√3/2 and sin θ < 0, with 0 ≤ θ < 2π. What is θ?
Show the answer Choice A
Why it is right
The cosine magnitude √3/2 is the Q1 cosine of π/6, so the candidates with cos = −√3/2 are the QII and QIII angles with reference π/6: 5π/6 (QII) and 7π/6 (QIII). The extra condition sin θ < 0 forces quadrant III, so θ = 7π/6. Check: cos(7π/6) = −√3/2 and sin(7π/6) = −1/2 < 0.
Why each other choice fails
- Choice B
- Picks the quadrant II angle with the same cosine. At 5π/6, cosine is −√3/2 but sine is +1/2, which violates sin θ < 0.
- Choice C
- Picks a quadrant IV angle with reference π/6. There cos is +√3/2 (positive), not −√3/2, even though sine is negative.
- Choice D
- Uses reference π/3 instead of π/6: cos(4π/3) = −1/2, not −√3/2. The magnitude √3/2 belongs to a 30° reference, not 60°.
Question 12 Hardest
What is the value of cos(17π/6)?
Show the answer Choice B
Why it is right
First reduce by a full turn: 17π/6 − 2π = 17π/6 − 12π/6 = 5π/6. Now evaluate cos(5π/6). That angle is in quadrant II with reference π − 5π/6 = π/6, so cos(π/6) = √3/2 and cosine is negative in QII: cos(5π/6) = −√3/2. Therefore cos(17π/6) = −√3/2.
Why each other choice fails
- Choice A
- Reduces correctly to 5π/6 but drops the quadrant II sign, reporting the positive cosine of the reference angle.
- Choice C
- Uses reference π/3 after reduction (or confuses 5π/6 with 2π/3): cos(2π/3) = −1/2. The reduced angle 5π/6 has reference π/6, not π/3.
- Choice D
- Either drops the sign after using the wrong reference, or evaluates cos of a QI angle such as π/3 without reducing 17π/6 at all.
Common mistakes
- Inverted conversion factor — multiplying degrees by instead of , or the reverse for radians → degrees. The leftover unit (or a huge non-special number) is the tell.
- Reference angle from the wrong axis — measuring to the -axis instead of the -axis, which swaps and values ( ↔ ).
- Sign drop in QII–IV — keeping the Q1 magnitude and forgetting ASTC. Cosine in QII and QIII is negative; sine in QIII and QIV is negative.
- Calculator in the wrong mode — feeding to a calculator still in degrees (or in radians). Exact special values on paper beat a mode error.
- Stopping at the reference angle — reporting or when the stem asked for or of the original angle.
- Confusing sine with cosine — on the unit circle, and ; swapping them is a free wrong choice for the test writer.
- Skipping coterminal reduction — reading as if were already between and , instead of reducing by first.
- Treating quadrantal angles as specials — inventing a half-radical for or instead of .
FAQ
Do I have to memorize the whole unit circle? Memorize Q1 specials and the quadrantal points; build every other quadrant with reference angle + sign. That is faster and less fragile than memorizing sixteen separate ordered pairs.
Is always radians? On the Digital SAT, an angle written with and no degree symbol is in radians. A degree symbol means degrees. Do not mix them inside one conversion step without the factor.
What is a reference angle? The acute angle between the terminal side and the nearest -axis. It is never measured to the -axis, and it is never negative.
Can Desmos replace the unit circle? It can check a decimal approximation after you set the mode correctly. It will not hand you in exact form, and it will happily compute the wrong mode. Use it as a check, not as step 1.
How do I enter a negative SPR answer?
Type the minus sign. Fractions such as -1/2 are accepted; do not leave the sign off and hope.